RE: [PHP] Php error with MySql
| From: | Jay Blanchard | Date: | Thu, 06 Jan 2005 19:12:27 +0000 |
| Subject: | RE: [PHP] Php error with MySql | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-205765@lists.php.net to get a copy of this message | ||
[snip]
I get the following error
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
resource in /home/wilmail/public_html/elblog.php on line 7
&n=& //error ends here
with the following bit of code
$qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC");
$nRows = mysql_num_rows($qResult);
$rString ="&n=".$nRows;
If I am just naming a variable how is the argument not valid?
[/snip]
Perhaps your query failed, but you've got no error checking.