Re: Php error with MySql

From: Date: Thu, 06 Jan 2005 20:59:45 +0000
Subject: Re: Php error with MySql
References: 1 2  Groups: php.general 
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----- Original Message ----- From: "Wil" <wil.hitchman@iape1096.org> To: <php-general@lists.php.net> Sent: Thursday, January 06, 2005 9:35 PM Subject: [PHP] Php error with MySql > I get the following error > > Warning: mysql_num_rows(): supplied argument is not a valid MySQL result > resource in /home/wilmail/public_html/elblog.php on line 7 > &n=& //error ends here > > with the following bit of code > > $qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC"); > Try " echo mysql_error() " just after your query. It's rather common to make typos or forget to select DB. > $nRows = mysql_num_rows($qResult); > $rString ="&n=".$nRows; > > If I am just naming a variable how is the argument not valid? > > Thanks, > > Wil > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >

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