Re: quicker arrays as func args?

From: Date: Thu, 13 Jan 2005 15:25:03 +0000
Subject: Re: quicker arrays as func args?
References: 1 2  Groups: php.general 
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M. Sokolewicz wrote:
Justin French wrote:
Hi all, Pretty sure this can't be done, but thought I'd ask any way... I have a function where the 3rd argument is an array.. function foo($a,$b,$c) {
    echo $a.$b;
    print_r($c);
} Obviously the function does more than that, but anyway, I want the calls to this function to look a little cleaner than this: foo("cat","dog",array("a"=>"1","b"=>"2","c"=>"3"));
Well you can always store the array in a variable and just pass the variable to the function as the third parameter. At least it would look prettier. $vars = array("a"=>"1","b"=>"2","c"=>"3"); foo("cat","dog",$vars);
is there any other way to define the array? foo("cat","dog",("a"=>"1","b"=>"2","c"=>"3")); or foo("cat","dog",{"a"=>"1","b"=>"2","c"=>"3"}); would be nice (Ruby has something like this), but I'm guessing it's not possible.
nope, that's the only way
Well... I suppose that you could create an object and then treat the object like an array (i.e. PHP5), but I doubt you want to do this unless you have a specific purpose for using the object in this way.
But, I'm asking just in case I've missed it in the docs. TIA --- Justin French, Indent.com.au justin.french@indent.com.au Web Application Development & Graphic Design
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