imagejpeg() output
| From: | Steven Simmons | Date: | Sat, 15 Jan 2005 16:39:16 +0000 |
| Subject: | imagejpeg() output | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-206461@lists.php.net to get a copy of this message | ||
I'm trying to write an object oriented system for saving my uploaded files to a blog.
I am using php to resize the original photos and save a thumbnail .
When I get all done, I want to do something like this:
$tempImageData = imagejpeg( $imageResource, '', 75 );
$outputHandler -> save ( $tempImageData );
Where the $outputHandler is an object that knows how/where to save the file.
However, I've noticed that imagejpeg() only returns a number 1.
This worked on my previous server, but I'm guessing my new server has a newer version of php.
What am I doing wrong? How can i pass the raw jpeg data to a function?