Re: Eval string to array

From: Date: Mon, 24 Jan 2005 19:30:33 +0000
Subject: Re: Eval string to array
References: 1 2  Groups: php.general 
Request: Send a blank email to php-general+get-207147@lists.php.net to get a copy of this message
Jochem Maas wrote:
Gerard Samuel wrote:
Im trying to evaluate a string representation of the output of var_export(), as an array. To make a long story short, Im using curl to fetch another php page, that uses var_export to echo out php data structures. The fetched data via curl, is a string. Something like -> array ( 'foo' => 'bar', )
something LIKE? or exactly that? anyway I don't have problems with this... php -r ' eval("\$arr = array ( \"foo\" => \"bar\", );"); $arr1 = var_export($arr, true); eval("\$arr2 = $arr1;"); var_dump($arr,$arr1,$arr2); ' ...took me a couple of mins to figure out how you could be....
For now, exactly like. This is what I extracted from your example for it to work -> $ret = str_replace("\n", '', curl_exec($this->curl_handle)); eval("\$arr = $ret;"); $arr1 = var_export($arr, true); var_dump($arr);
I would like to convert this to a real array. Im currently trying this -> $ret = curl_exec($this->curl_handle); $str = '$array = $ret;';
this is your problems. its to do with string interpolation. your exec() call is equivelant to $array = $ret; guess what that makes $array? so it should be: exec("\$array = $ret;"); which will replace the string $ret into the string to be exec()'ed. alternatively: exec('$array = '.$ret.';'); geddit?
gotit
eval($str); var_dump($ret, $array);
next time paste the actual var_dump output, its easier. :-)
It was in the original email. Just not where you thought it would have been ;) Thanks for your help.

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