Re: I need to create a search that will search partial filesnames of images and display the images. Basically, I have a folder on theinternet that
has security camera images dumped into it with a file namelike this:

From: Date: Thu, 03 Feb 2005 21:58:48 +0000
Subject: Re: I need to create a search that will search partial filesnames of images and display the images. Basically, I have a folder on theinternet that
has security camera images dumped into it with a file namelike this:
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"Vin" <vin@vjg.cc> wrote in message news:20050203211056.75336.qmail@lists.php.net... > "Marek Kilimajer" <lists@kilimajer.net> wrote in message > news:420261B7.4030305@kilimajer.net... > > Vin wrote: > > > I need to create a search that will search partial files names of images > and > > > display the images. Basically, I have a folder on the internet that has > > > security camera images dumped into it with a file name like this: > > > > > > MDcameraname20050109104846001N38B.jpg > > > MDcameranameYYYYMMDDHHMMSS001N38B > > > > > > So what I would like to create is a search that will allow a user to > input > > > the year, month, day, and hour, and have the website display the images > from > > > that hour. Could someone help me with this? > > > > > > Thanks in advance, > > > Vinny > > > > > > > http://sk2.php.net/manual/en/function.glob.php > > > thanks, that is perfect. Now I have a follow up question if you don't mind. > How can I take $filename and break it apart to display the time/date the > picture was taken in a nice readable format? > > here is my code: > > <?php > $x = 0; > $count = 0; > $matches = glob("*$y$m$d$h*.JPG"); > if ( is_array ( $matches ) ) > { > foreach ( $matches as $filename) > { > if ($x < 4) > { > echo "<td>"; > echo "<a href=javascript:pop('"; > echo $filename; > echo "');>"; > echo "<img src='"; > echo $filename; > echo "' border=0 width=240 height=180></a>"; > $count = $count+1; > echo "<br>"; > echo $filename; > echo "</td>"; > $x = $x + 1; > } else { > echo "</tr><tr>"; > $x = 0; > } > } > } > > echo "<br><br>"; > echo $count . " images found"; > ?> Here is an example of what I'm talking about: Filename looks like this: MDcameraname20050108124537001A.JPG I would like the output to look like this: 01/08/2005 12:45:37

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