Re: Re: Question re empty query

Okay, guys, I hope I'm getting closer with your help here but I am still highly confused (that's actually a general blanket statement these days). I've taken your advice and made several changes, On 9 Mar 2005, at 13:44, Jochem Maas wrote:

M. Sokolewicz wrote:

Jackson Linux wrote:

Hi, This: if (isset($_GET['r']) &&

     !empty($_GET['r']) &&
     ($r = intval($_GET['r'])) ){

does nobody notice the last 'bit' of the if expression?? if the IF statement evaluates to true then $r _has_ been set!!!

That makes sense now.

$r = "{$_GET['r']}"; //Set the variable $r to mean the category number

gods, that's an ugly statement... why don't you simply use $r = $_GET['r']; ????

that leaves him completely open to SQL injection. but your right in that writing this: $r = "{$_GET['r']}"; ... is just plain wasteful, pointless and looks ugly. and given the fact that $r is already set (see above) there is no need to set it again at all.

I see that now; thanks, I removed it

I think you almost there Jackson, keep hacking :-) Thanks for the encouragement! But there's more...

$sort = "ORDER BY cv.sort"; } else { $where = ''; $fields = 'cv.cv_id,cv.category,dates,cv.job_title,cv.company,cv.job,cv.sort, jobcat.category'; $sort = "ORDER BY cv.sort"; } //Make the sql based on the joining of the table and intersection table $sql = " SELECT cv.cv_id,cv.category,dates,cv.job_title,cv.company,cv.job,cv.sort,jobcat .category FROM cv, cvjobcats, jobcat WHERE cvjobcats.cv_id=cv.cv_id AND cvjobcats.jobcat_id = $r AND jobcat.jobcat_id=cvjobcats.jobcat_id"; Works whenever there is an ?r= specified. When there is no r specified it chokes on WHERE cvjobcats.cv_id=cv.cv_id AND cvjobcats.jobcat_id = $r AND jobcat.jobcat_id=cvjobcats.jobcat_id"; because there's no value to $r. it also opens me up to allowing anyone to state *anything* after the ?. So can I make an else statement which will say that if there's no r= or a wrong r= or even no ? at all then it should print a menu to $r's which actually exist in the database? How? Thanks in advance!!!

You have 3 conditions in a single expression. Split that expression up

Jackson got that bit from me - I don't think he is fully aware of what that expression is doing! the 'sum' of those conditions determines that either $r is 'good' or 'bad' (whether $r is garbage or not set didn't seem like a difference worth bothering with)

No, I didn't and I actually still don't. I've implemented the change below, breaking up the if(isset)$_GET['r']) bit (making it easier to follow indeed, thank you!) but I am confused as to how to break that three-condition statement split based on that change.

into multiple expressions, so you can check each (or a combination of 2) individually.

this is a good idea to better understand what is going on!

so, instead of: if (isset($_GET['r']) && !empty($_GET['r']) && ($r = intval($_GET['r']))){ do: if (isset($_GET['r'])) {

    if(!empty($_GET['r']) && ($r = intval($_GET['r']))){
        // do whatever
    } else {
        // something boring
    }

} else {

    // not set

}

The code below is where I am now. I'm trying to document a bit better, and clean it up. And I still don't have any clue as to how to make it redirect if someone requests no ?r= or a bad one. Can someone help please?

<snip> if (isset($_GET['r'])) { if(!empty($_GET['r']) && ($r = intval($_GET['r']))){

          $fields = '*';
	  $where = "WHERE cvjobcats.cv_id=cv.cv_id AND cvjobcats.jobcat_id = '$r' AND jobcat.jobcat_id=cvjobcats.jobcat_id";
          $sort = "ORDER BY cv.sort"; // Assemble the category items in r=x

} else { // Is this where I'd say IF no $r is set then redirect? } } //Make the sql based on the joining of the table and intersection table $sql = " SELECT cv.cv_id,cv.category,dates,cv.job_title,cv.company,cv.job,cv.sort,jobcat.category FROM cv, cvjobcats, jobcat $where $sort "; $result = mysql_query($sql); $cv = mysql_fetch_assoc($result); $table_of_contents = array(); $result = mysql_query($sql); if (!$result) { echo "Could not successfully run query ($sql) from DB: " . mysql_error(); exit; } if (mysql_num_rows($result) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } </snip> Thanks in advance!! --Jack