RE: [PHP] newbie php/mysql need help

From: Date: Sun, 13 Mar 2005 22:45:49 +0000
Subject: RE: [PHP] newbie php/mysql need help
References: 1  Groups: php.general 
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Simple but should work. $query = " SELECT DISTINCT (brand), COUNT( brand )FROM machines where category like 'sold' group by brand;"; $result = mysql_query($query) or die(mysql_error()); While($data = mysql_fetch_array($result)) { echo "<p>{$data[0]} - {$data[1]}</p>\n"; } -----Original Message----- From: p80 [mailto:p80@free.fr] Sent: Sunday, March 13, 2005 4:35 PM To: php-general@lists.php.net Subject: [PHP] newbie php/mysql need help I do a mysql request like this one: SELECT DISTINCT (brand), COUNT( brand )FROM machines where category like 'sold' group by brand" I get this from mysql: brand COUNT( brand) brandx 4 brandy 12 how can I echo this result in php? thanx in advance Pat -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

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