RE: [PHP] Damn escaping... Grunf...
| From: | YaronKh at clalit dot org dot il | Date: | Mon, 21 Mar 2005 13:49:59 +0000 |
| Subject: | RE: [PHP] Damn escaping... Grunf... | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-211184@lists.php.net to get a copy of this message | ||
Hi
Try using " instead of '
Meaning you should write:
Print ("<a href =\"http://www.dte.ua.pt/cv/email=?".$recordSet->fields[0].
"\" <br />");
-----Original Message-----
From: Mário Gamito [mailto:gamito@tuxdoit.com]
Sent: Monday, March 21, 2005 12:50 PM
To: php-general@lists.php.net
Subject: [PHP] Damn escaping... Grunf...
Hi,
I want this code to display peoples' names within an hyperlink.
I'm tired of trying different ways, read all about it in PHP's manual,
but i can't get it there.
You can visit http://www.dte.ua.pt/cv
In the rightmost column it is suposed to apear two name below "Links",
but... it doen't, becuase i can't straight the escaping :(
Any help would be apreciated.
The code follows my signature.
Warm Regards,
Mário Gamito
--
// select names to display in the right column
$recordSet = &$conn->Execute('SELECT name FROM users');
while (!$recordSet->EOF) {
print ('<a href=\'http://www.dte.ua.pt/cv/email=?' .
$recordSet->fields[0] . '\'' . '<br />');
$recordSet->MoveNext();
}
--
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