Re: Problem with header in an if

From: Date: Sat, 26 Mar 2005 12:42:53 +0000
Subject: Re: Problem with header in an if
References: 1  Groups: php.general 
Request: Send a blank email to php-general+get-211617@lists.php.net to get a copy of this message
Jay Blanchard wrote:
[snip]
/* send the errors to the interface and exit*/ if('' !== $errorsReported){ for($i = 0; $i < count($errorsReported); $i++){ echo $errorsReported[$i]; }
unset($errorsReported); print_r($errorsReported);
} else { /* reload the empty interface */
a quick echo statement here to check that this block is running when you expect it to might tell you something... but you have probably already plastered your code with echo/print statements to determine the flow :-) [/snip] Well, the array still appears, it is empty and unset (see modified code above) does not get rid of it. Here is how it comes back .... Array ( [0] => [1] => [2] => [3] => )
Well maybe its just me, but you are comparing an array with a string if ('' !== $errorsReported), which doesn't make any sense. Try this instead: if (is_array($errorsReported)) { echo implode("",$errorsReported); } else { header(....); }

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