Re: Split command problem

On Apr 10, 2005 8:27 PM, Russ <russbucket@centurytel.net> wrote: > I have been trying to get the following code working. I keep getting an error > on line nine. It looks simular to the example in the PHP online manual. If I > substitute a print command for line nine I get the correct information from > $_POST[username]. I must be missing or have an extra a quote but I cannot > figure out where. > > <?php > //check for required fields from the form > if ((!$_POST[username]) || (!$_POST[password])) { > header("Location: memberlogin15.7.php"); > exit; > } > if(preg_match("/[A-Z]/", substr("$_POST[username]", 0, 1))) > { > name($fname, $lname) = split('[/\s+/]', "$_POST[username]"); Where is your 'name' function and what does it do? I'd do: $name = explode( ' ', $_POST[ 'username' ] ); echo "First Name: $name[0] Last Name: $name[1]"; > //echo "First Name: $fname; Last Name: $lname\n; > echo "first letter is uppercase"; > } > else > { > echo "first letter is not uppercase"; > } -- Greg Donald Zend Certified Engineer http://destiney.com/