Re: call_user_func_array and mysqli_stmt_bind_result

Hello, mysqli_stmt_bind_result() is a special function that takes parameters by reference after the first one. When you code: mysqli_stmt_bind_result ($stmt, $arr[1], $arr[2]); Then $arr[1] and $arr[2] can be passed by reference. But when you code: $arr[0]=$stmt; $arr[1]=''; $arr[2]=''; call_user_func_array ('mysqli_stmt_bind_result',$arr); Then '' and '' cannot be passed by reference. It should be: $prmlst = array($stmt,&$arr[1],&$arr[2]); call_user_func_array ('mysqli_stmt_bind_result',$prmlst); Enjoy, --------------------- Skrol29 www.tinybutstrong.com --------------------- Patrick a écrit :

Hi, This is working (as a packet of crackers): ... mysqli_stmt_bind_result ($stmt, $arr[1], $arr[2]); ... This I cannot get to work: ... $arr[0]=$stmt; $arr[1]=''; $arr[2]=''; call_user_func_array ('mysqli_stmt_bind_result',$arr); ... I'm not sure if what I try to do is possible in any way? Btw, this is Win PHP v5.0.3 , Apache v2.0.53, Mysql v5.0.2-alpha-nt. cheers and thanks, Patrick from Belgium (Brussels)