Re: Thanks but problem again! Re: [PHP] PHP script problem (with MySQL)

I think that in your database it is : substring(loc, 1, 3) as loc1 Anyway, the error is not where you are getting the message, the query failed and this you don't have a valid resource to ask the number of rows or do anything else. You should add an 'or die("message: " . mysql_error()) to your query to trap the error. Satyam "Sugimoto" <sugimoto@momat.go.jp> wrote in message news:005301c54556$29488650$d405a8c0@sugimoto... > Thank you, Richard, > > I simply change this part > (select * from openart_table) into > (select substring(loc1, 1, 3) as THREE_LETTER_CODE, * from openart_table) > but Ive got this error, whats wrong with it? > > Warning: mysql_num_rows(): supplied argument is not a valid MySQL result > resource in c:\apache......\openart\test\openart_search.php on line 98 > Records Found > > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL > result > resource in c:\apache....\openart\test\openart_search.php on line 100 > > Cheers