Re: Function shall receive Pointer to Array

I don't know what to tell you, that code should work (it does work, exactly as you gave it in my PHP 5). Chris Fred Rathke wrote:

Hello, how can a function get a pointer to an array? This does not work. I use PHP4. $t = array("test" => "unchanged"); echo "<br>testarray unchanged:\"".$t['test']."\""; changearray($t); echo "<br>testarray hopefully changed:\"".$t['test']."\""; function changearray(&$myarray) { $myarray['test'] = "changed"; } Before I tried it on my own I read this page: http://de2.php.net/manual/en/language.references.whatdo.php Be so nice to search for this string: "The second thing references do is to pass variables by-reference. This is done by making a local variable in a function and a variable in the calling scope reference to the same content. Example:" The following example I used. I only tried to do it with an array instead of a variable. What I need to read again to find my own mistake? I know some of php's commands work with an internal copy of a content. Thanks for your help and advice.