Re: Array of objects
| From: | Jochem Maas | Date: | Fri, 06 May 2005 11:16:44 +0000 |
| Subject: | Re: Array of objects | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-214612@lists.php.net to get a copy of this message | ||
Thomas Hochstetter wrote:
Spiraleye.Studios Hi there, I need help with arrays. What I want to do is to have an array of the following structure: $mod=array( ‘name’=>new NameObject());class Test { function Test($str = '') { echo $str; } } $_GET['module'] = 'testmod'; $mod = array( 'testmod' => 'Test' ); if (isset($mod[$_GET['module']]) && class_exists($c = $mod[$_GET['module']])) {^ -- looks like your single quotes got mangled in my email client.
$Site = new $c;
// $Site = new $c('Testing');
} else {
die ('Can't create module object');
}
... and if that doesn't give you the knowledge/inspiration/lighbulb-moment
to fix whatever it is your trying to do then please mail the list again
and explain what _and_ why you are trying to do whatever it is you're trying to
do (this helps people to understand thereby having a better chance of
offering some helpful advice!)
Then later in the page I want to go $Site = $mod[$_GET[‘module’]] (or something like that) to instantiate a new object. The problem is, if done the way above it will try to instantiate the object right there and then in the array (defeating the purpose), if I put it in quotes and try to use something like: (object)eval($mod[$_GET[‘module’]]) it does not instantiate the object.well assuming no syntax error occurs (eval will return false is such a case) then I bet it actually does, only your eval statement isn't assigning the new object to anything!... besides which you are casting the return value of eval to an object which is pointless for 2 reasons: 1. casting NULL to an object gets you nowhere (atleast not in this case) 2. casting an object to an object get you... nowhere :-) so....: $mod = array( 'name' => 'return new NameObject()'); $Site = eval($mod['name']); PS - do you know what a reference is? (in terms of [php] variables)? understanding references with regard to objects (especially if your using php4) is a really good addition to your coding arsenal (it will save you time hunting inexplicable bugs - often such 'bugs' are nog longer inexplicable! and allow you to increase the speed of your code) PPS - using eval() is hardly ever the only option, and given that eval() is very slow its best to avoid it at all costs (assuming there is another way to do what you want)... also eval() _can_ be a security risk, if you do something like: eval($_GET['command']) without santizing the contents of $_GET['command'], hopefully you can see why.
Is there a way to do this? Thanks Thomas * **SPIRAL EYE STUDIOS *** P.O. Box 37907, Faerie Glen, 0043 Tel: +27 12 362 3486 Fax: +27 12 362 3493 Mobile: +27 83 258 2669 Email: info@spiraleye.co.za <mailto:info@spiraleye.co.za> Web: www.spiraleye.co.za <http://www.spiraleye.co.za>