counting ocuring words in a string
| From: | Merlin | Date: | Tue, 17 May 2005 10:00:24 +0000 |
| Subject: | counting ocuring words in a string | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-215379@lists.php.net to get a copy of this message | ||
Hi there,
I am trying to find a way to count the number of times (if any) words are inside a string. So I played around with ereg, preg_match_all and so on, but could not put together a working code.
Can anybody help me on that?
This is the current code:
function count_words($str, $words) {
if(is_array($words)) {
foreach($words as $k => $word) {
$pattern[$k] = "/\b($word)\b/is";} } else { $pattern = "/\b($words)\b/is"; } return ereg( $pattern, $str); } $words = 'php language'; $str = 'One language which is great is php. PHP works great!'; $num_hits = count_words($str, $word); echo $num_hits; I would like to get an case insensitive result. In this example: 3 I am a bit lost on this one. Thank you for any help. Merlin