Re: looping through an array problem

From: Date: Sun, 05 Jun 2005 23:34:00 +0000
Subject: Re: looping through an array problem
References: 1 2 3 4 5 6  Groups: php.general 
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Ah. I just remembered one reason I had done it involving the art_id field: I have more publishers in the db than are currently associated with artworks. I don't want a publisher to appear unless there is at least one image associated with it. So I did this to avoid having people see a link to the Sneezy Acres Tribune only to arrive at the next page and see, "There are no images associated with this publisher." Jochem Maas wrote:
Jack Jackson wrote:
M. Sokolewicz wrote:
Jack Jackson wrote:
Thanks for all the replies. Jochem, thank you for this code, which will take me all night to understand (though I bet it works). I also note that SELECT DISTINCT worked here, too Also as many of you noticed before me, the art_id was in there as a fly in the ointment.
by that statement I ment the exact same thing Jochem ment in his 2nd part; I have NO idea why you're selecting *ANYTHING* from the arts table... it's *useless* if you don't need the data...
Er, yes, that was what I meant: I had unintentionally included that bit.Thank you for your help.
Er, Jack - your original query was: SELECT art.art_id,art.publisher_id,publisher.publisher_name, FROM art LEFT JOIN publisher ON publisher.publisher_id=art.publisher_id which is a selection on the art table... ( with a typo) if you did: SELECT art.publisher_id,publisher.publisher_name FROM art LEFT JOIN publisher ON publisher.publisher_id=art.publisher_id nothing would change. and if you did: SELECT publisher.publisher_id,publisher.publisher_name publisher i.e. not 'unintentionally' selecting from the arts table. then you would not have had a problem in the first place?! I think I'm missing something ;-)


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