Re: Passing a function & arguments to a function

David Johnson wrote:

I am trying to pass a function as an argument to another function, and then run the first function from within the second function. Example:

    function function0($arg0, $arg1, $arg2) {

        function2();

    }

        function3();
        do_function($arg5);
        function4();

    }

    function1(5, 100, function0($arg0, $arg1, $arg2));
    

<? function func0($arg0, $arg1, $arg2) { /* do stuff */ } function func1($arg1, $callback, $callbackArgs = /*order!*/array()) { func3(); func4(); if (is_callable($callback)) { $retval = call_user_func_array($callback, $callbackArgs); } } func1(5, 'func0', array($arg0, $arg1, $arg2)); ?> the 'func0' in : func1(5, 'func0', array($arg0, $arg1, $arg2)); could be something like: array('ClassName', 'MethodName') array($YourObject, 'MethodName')

In the above example, I am running function1(), which includes function0 as an argument. I am trying to pass "function0($arg0, $arg1, $arg2)" as an argument to function1, which will then execute the passed function, including its passed arguments. I have had mild success by splitting "function0($arg0, $arg1, $arg2)" into 2 parts of "function0" and "$arg0, $arg1, $arg2", and then passing both parts as an argument, such as $arg5 & $arg6, and then doing this:

    function function1($arg3, $arg4, $arg5) {

            $args_array = explode(", ",$arg6);
            $arg5($args_array[0],$args_array[1],$args_array[2]);

        }
    

However, this causes all of my arguments in the array to be evaluated as strings and not resources, which they may be. Also, I don't really like this method, and would prefer a much "cleaner" way of doing things.