Re: Re: date problem

Hi Jasper and thanks for the quick reply. something tells me it's not a straightforward SQL query that I have to use here but a logic using PHP and SQL. Mario ----- Original Message ----- From: "Jasper Bryant-Greene" <jasper@bryant-greene.name> To: <php-general@lists.php.net> Sent: Wednesday, June 29, 2005 4:28 AM Subject: [PHP] Re: date problem

Firstly, this shouldn't be in the PHP list, as you're asking for help with SQL. Mario netMines wrote:

carrental_from (datetime field) carrental_to (datetime field) carrental_price (datetime field) [rates are per hour]

carrental_price shouldn't be a datetime field, as it isn't a datetime value.

The values I have are like: 0000-00-00 00:00:00,0000-00-00 07:00:00,10 (all year around 00:00-07:00) 0000-00-00 07:00:00,0000-00-00 00:00:00,20 (all year around 07:00-00:00) 2005-12-22 07:00:00,2006-01-02 00:00:00,15 (christmas period 00:00-07:00) 2005-12-22 00:00:00,2006-01-02 07:00:00,25 (christmas period 07:00-00:00) The user selects dates ($from - $to) to rent a car and he gets the price accordingly. I can do a (($to-$from)/60/60) and get the total number of hours but depending on the date and time you get a different result. Can anyone help with the SQL?

Read up on the MySQL DATEDIFF() function, if you are using MySQL. Other DBMSs should have an equiv. function. Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php