Help with preg_replace

Hi list I need help to solve a preg_replace() problem. I have a snippet of html code that contains some links. I have an array thats contains all links inside that snippet of html code. What i need to do is replace all the links in the code by another on. So this is what i´m trying to do: //links that should be replaced $url = array( array("id" => 0, "url" => "http://www.silika.com.br/conarh/mala3"), array("id" => 1, "url" => "http://www.conarh.com.br"), array("id" => 2, "url" => "http://www.conarh.com.br/main_frameset.php?secao=congresso&idioma=port&pagina=http://www.conarh.com.br/programacao/pub/index.php?tipo_barra=laranja"), array("id" => 3, "url" => "http://www.conarh.com.br/main_frameset.php?secao=congresso&idioma=port&pagina=http://www.conarh.com.br/mensagem/pub/mensagem.php?id_mensagem=insc_temp&tipo_barra=laranja"), array("id" => 4, "url" => "http://www.silika.com.br/conarh/patrocinio/patrocinio.htm")); $escape_chars = array("?", "/"); $escaped_chars = array("\?", "\/"); $matches = array(); foreach ($url as $link) { $pattern = "/" . str_replace($escape_chars, $escaped_chars, $link["url"]) ."/"; $newurl = URL_LINKS."linkId=".$link["id"]."&rId=1"; $body_html = preg_replace($pattern, $newurl, $body_html, 1); } This works fine for links with id 0, 1 and 4. But i haven´t been able to figure out how to match and replace links with id 2 and 3. How do I get my regex to match and replace those links as well? Any help appreciated. Thanks.