Re: date() problem

From: Date: Thu, 07 Jul 2005 16:12:31 +0000
Subject: Re: date() problem
References: 1 2 3  Groups: php.general 
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Philip Hallstrom wrote:
of leap years between the two dates. Leap years occur every 4 years, and 17 / 4 = 4.25, so there were 4 leap years between 7/6/88 and 7/6/05 and
Just to nitpick... :-) http://en.wikipedia.org/wiki/Leap_year The Gregorian calendar adds an extra day to February, making it 29 days long, in years where the quotient has no remainder when divided by 4, excluding years where the quotient has no remainder when divided by 100, but including years where the quotient has no remainder when divided by 400. So 1996, 2000, and 2400 are leap years but 1800, 1899, 1900 and 2100 are not.
Touche! One more reason not to use the OP's method but rather the one posted by Richard Lynch. kgt

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