Re: Re: alternating colors

Couldn't you shorten that and do... $colors = array("red","blue"); echo "<table>\n"; for ($i = 0; $i < 100; $i++) { $j = $i % 2; printf("<tr bgcolor=%s><td>Row %s (color #%s)</td></tr>\n", $colors[$j],$i,$j); } echo "</table>\n"; -philip In article <Pine.GSO.4.02A.10010231023590.18191-100000@lagrange.rutgers.edu> you write: >Hi Rodney, > >This works: > ><?php > >function foo($n) { > $mod = 3; > return ((($n % (2*$mod)) / $mod ) < 1); >} > >$colors = array("red","blue"); > >echo "<table>\n"; >for ($i = 0; $i < 100; $i++) { > $j = foo($i); > printf("<tr bgcolor=%s><td>Row %s (color > #%s)</td></tr>\n", > $colors[$j],$i,$j); >} >echo "</table>\n"; > >?> > > >---------------------------------------------------------------- >Matthew Leingang http://www.math.rutgers.edu/ >Rutgers University leingang@math.rutgers.edu >Department of Mathematics "This signature needs no quote." > >On Thu, 19 Oct 2000, Rodney Davis wrote: > >> I am trying to alternate table bgcolor with each iteration of >> the following loop: >> >> print >> >> "<td><b>One</b></td>\n<td><b>Two</b></td>\n<td><b>Three</b></td>\n</tr>"; >> foreach ($list as $row) >> { >> print "<tr>\n"; >> print "<td> $row[one] </td>\n<td> $row[two] "; >> print " </td>\n<td> $row[three] >> </td>\n</tr>\n<tr><td colspan=3> >> $row[four] </td>\n</tr>\n"; >> print "<tr>\n<td colspan=3> $row[five] </td>\n"; >> print "</tr>\n"; >> } >> print "</table>"; >> >> So that every three rows will be a single grouped color different from the >> next three rows. >> Does anyone know how to do this ? >> >> Thanks >> >> rodney >> >> >> >> [ Part 61: "Included Message" ] >> > > >-- >PHP General Mailing List (http://www.php.net/) >To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net >For additional commands, e-mail: php-general-help@lists.php.net >To contact the list administrators, e-mail: php-list-admin@lists.php.net >