Re: function with argument of type array

Marcus Bointon wrote:

On 28 Jul 2005, at 12:07, André Medeiros wrote:

On Thu, 2005-07-28 at 11:08 +0200, marc serra wrote:

Hi, i want to know if it is possible to create a function and declare that one of its arguments is array type. In fact i want to do something like this function test(String $litteral, array $foo){

unless String is a class you defined that won't work at all. basic data types cannot be hinted (e.g. bool, int, string, float)

There is no way to do that. What you _CAN_ do, to ensure you're getting an array is:

There IS a way to do exactly this. It's called type hinting and it's a PHP 5 feature:

for a split second I was about to say a word start with 'bull', but Marcus is more or less correct - typehints for classes has existed since the beginning of php5, the ability to typehint arrays is aparently being included in php5.1 (still in beta). thanks Marcus for the heads up. :-) ================= now don't get me started on the fact that 'they' pulled the plug on being able to do they following - I feel the breath of some purist overlord breathing down my neck: class Test { /* ... */ } function foo(Test $t = null) { /* ... */ } (the above worked in the first few betas of php5.0) if a php 'God' reads this (and at least one of you is kind enough to grace us with his presence on this list) - please reconsider allowing typehints with defaults of NULL (only NULL and nothing else is more than enough for me!).

http://www.php.net/manual/en/language.oop5.typehinting.php Marcus