Re: trying to understand PHP unpack();

Sonia wrote:

Hi In Perl I have a part of a script.... # cut.. my $line = '!v2005*08|05+09?04^19*!'; ^-- note how my email client screws up your original

string... something I don't really understand...

my ( $s_code, $year, $month, $day, $hour, $minute, $second, $e_code ) = unpack ( "x1 A1 A4 x1 A2 x1 A2 x1 A2 x1 A2 x1 A2 A1", $line ); print $s_code . "\n"; print $year . "\n"; print $month . "\n"; print $day . "\n"; print $hour . "\n"; print $minute . "\n"; print $second . "\n"; print $e_code . "\n"; sleep 10; # so we can see it in the command window In Perl this runs without trouble, in PHP it does not seem to work the same way. Can someone explain to me what I need to do differently to allow PHP to understand what I am trying to do! <? my $line = '!v2005*08|05+09?04^19*!'; ^-- this will cause a parse error

$output = unpack ( "x1 A1 A4 x1 A2 x1 A2 x1 A2 x1 A2 x1 A2 A1", $line ); print_r ( $output ); ?>

I have next no knowledge wroth speaking of concerning binary data - and the string screw problem mentioned above makes it impossible for me to determine whether I am really on the right path here but take a look at the following: $line = "!v2005*08|05+09?0419*!"; $output = unpack ( "x1 A1 A4 x1 A2 x1 A2 x1 A2 x1 A2 x1 A2 A1", $line ); $output2 = unpack ( "x1A1A4x1A2x1A2x1A2x1A2x1A2A1", $line ); $output3 = unpack ( "x1/A1/A4/x1/A2/x1/A2/x1/A2/x1/A2/x1/A2/A1", $line ); $output4 = unpack ( "x1_a/A1_b/A4_c/x1_d/A2_e/x1_f/A2_g/x1_h/A2_i/x1_j/A2_k/x1_l/A2_m/A1_n", $line ); var_dump( $output, $output2, $output3, $output4 );' this page: http://nl2.php.net/unpack ... does mention that the php unpack() implementation is somewhat different to the perl one (btw I'm a complete perl luddite! - I don't think my brain can cope with that much cryptic crap ;-) - that said thank Larry for PCRE!) I'd be very grateful if you report back on your progress - I for one can definitely learn something here! rgds, jochem ps - welcome to phpland perlie ;-)

Thanks SD