RE: [PHP] Tidying code for PHP5.0.5/PHP4.4.0

Rasmus Lerdorf wrote: > Michael Sims wrote: >> When used as an expression, an assignment evaluates to whatever is >> on the right side of the assignment operator, not the left. >> Example: [...] >> foo($a = 5); >> and >> foo(5); >> >> are exactly the same... > > The value passed is the same, but when passed as $a=5 then the value > has a symbol table entry associated with it whereas if you just pass > in 5 it doesn't. That means that: > > function foo(&$arg) { $arg =6; } > > will work if you call: foo($a=5); > but you will get an error if you have: foo(5); Oops, sorry for posting misinformation, I was not aware of the above... Thanks for the info.