Re: working with xml from a php file for xsl transformations
| From: | Jasper Bryant-Greene | Date: | Fri, 30 Sep 2005 05:57:32 +0000 |
| Subject: | Re: working with xml from a php file for xsl transformations | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-223447@lists.php.net to get a copy of this message | ||
jonathan wrote:
//neither of these work //$menu=file_get_contents(urlencode('menu_render.php? menu_id=4&format=xml')); $xml->load('menu_render.php?menu_id=4&format=xml');You need to pass those get variables through a web server, otherwise you're looking for a file called "menu_render.php?menu_id=4&format=xml" which doesn't exist. Try: $menu = file_get_contents( 'http://www.yoursite.com/yourpath/menu_render.php?menu_id=4&format=xml' ); -- Jasper Bryant-Greene Freelance web developer http://jasper.bryant-greene.name/