Re: Testing for an empty array (with null values)

zzapper wrote:

Hi, I can use if (count($somearray) > 0) to test for an empty array.

why don't you test it. $a = array(); $b = array(null, null, null); $c = array(false, false); $d = array(1, 1, 1); echo "array \$a: \n---------------------------\n"; var_dump(empty($a), count($a), array_filter($a), array_values($a)); echo "array \$b: \n---------------------------\n"; var_dump(empty($b), count($b), array_filter($b), array_values($b)); echo "array \$c: \n---------------------------\n"; var_dump(empty($c), count($c), array_filter($c), array_values($c)); echo "array \$d: \n---------------------------\n"; var_dump(empty($d), count($d), array_filter($d), array_values($d));

It is possible to have an array with null values which is effectively empty but fails the above as it's count (I belive is greater than 0).

look above.

Any ideas

plenty. hopefully the code above give you a few too :-)