Re: Help with logic :(

From: Date: Tue, 11 Oct 2005 17:45:51 +0000
Subject: Re: Help with logic :(
References: 1 2 3 4 5 6 7 8 9  Groups: php.general 
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$result = mysql_query($query) or die(mysql_error()); On 10/11/05, Silvio Porcellana <sporc@tin.it> wrote: > aaronjw@martekbiz.com wrote: > > <?php > > > > include ("../utils.inc"); > > > > $date = date("U"); > > $dateExpire = $date + 90 * 86400; > > > > $code = "jack"; > > > > $query = "INSERT INTO CouponTable VALUES > > > > ('','$date','0','$code','preset','$dateExpire','3.75')"; > > > > $result = mysql_query($query); > > > > echo mysql_error($result); > > > > ?> > > > > This SHOULD error out but I'm getting the error instead. > > > > It's just a test page to test my logic... > > > > If you read carefully this page: > > http://php.net/mysql_error > > you will notice that it says that you need to pass to mysql_error *the > MySQL connection*. Not the resource returned by mysql_query. > > HTH, cheers > Silvio > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >

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