Re: can't get printf() to work
| From: | Web Admin | Date: | Sat, 28 Oct 2000 17:55:49 +0000 |
| Subject: | Re: can't get printf() to work | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-22471@lists.php.net to get a copy of this message | ||
Hi Gary,
Consider using this instead:
print("<tr><td>".$myrow[i]."</td><td>");
It will probably work.
Ahmad Anvari
----- Original Message -----
From: Gary
To: php-general@lists.php.net
Sent: Saturday, October 28, 2000 9:13 PM
Subject: [PHP] can't get printf() to work
Hi,
I can get printf to print the result form a db. I have check the query
and all is well and i use mysql_num_rows() after the queries and it
gives me the correct result. Here is the latest variation of what i am
using. The echo table cells works fine, not the printf.
while ($myrow=mysql_fetch_array($result));
echo "<table border=2 bordercolor=#000000>\n";
echo
"<b><tr><td>ID</td><td>checkbox</td><td>Username</td><td>Password</td><td>Email</td></tr></b>\n";
printf("<tr><td>%s</td><td>%s</td><td>%s</td><td>%s</td><td>%s</tr>\n",$myrow["id"],$myrow["checkbox"],$myrow["username"],$myrow["password"],$myrow["email"]);
echo "</table>\n";
Thanks
Gary
--
The sad thing about artificial intelligence is that it lacks artifice
and therefore intelligence.Jean Baudrillard (1929), French semiologist.
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