Re: PHP/MySql noob falls at first hurdle

From: Date: Fri, 09 Dec 2005 14:23:57 +0000
Subject: Re: PHP/MySql noob falls at first hurdle
References: 1  Groups: php.general 
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On 12/9/05, Paul Jinks <paul@pauljinks.co.uk> wrote: > Hi all > > I've been asked to put simple database interactivity on an academic > site. They want users to enter a few details of their projects so other > researchers can search and compare funding etc. How difficult can that > be, I thought.... > > I've built the database in MySQL and entered some dummy data, and I'm > now trying in the first place to get the data to display with a simple > select query to display the variable "projTitle" from the table > "project" thus: > > <head> > <snip> > <? > > $SQLquery = "SELECT projTitle FROM project"; > $result = mysql_query($SQLquery) > or die ("couldn't execute query"); > mysql_close($connect) > > ?> > > <body> > <p>Result of <b><?=$SQLquery ?></b></p> > > <p> > <? > while($ouput_row = mysql_fetch_array($result)) { > ?> > <?=$output_row["projTitle"]?><br /> > <? > } > ?> > > </p> > </body> Try to check the key of your result row with a print_r or a var_dump command. Brice Favre http://pelmel.org/

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