Re: array of checkbox values
| From: | James Benson | Date: | Wed, 11 Jan 2006 23:30:44 +0000 |
| Subject: | Re: array of checkbox values | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-228503@lists.php.net to get a copy of this message | ||
Do something like:
$checkboxes = array('food','drink','smoking');
// display the checkboxes
foreach($checkboxes as $checkbox) {
echo "$checkbox: <input type="checkbox" name=\"$checkbox\" />";
}
Then when processing the form input check if each of the $checkboxes array values are present, if not, you can set to something else such as N, like so.
$sent_data = array();
foreach($checkboxes as $checkbox) {
if(isset($_REQUEST[$checkbox])) {
$sent_data[$checkbox] = 'Y';} else {
$sent_data[$checkbox] = 'N';} } James Sjef Janssen wrote:
Hallo, I have a form with a number of checkboxes grouped together. The value of these boxes is stored in an array: $used[]. Now I found that the value of checked boxes (value = 'Y') are stored in the array while non checked boxes are not stored at all. This makes the array incomplete as I want to have all checkbox values in the array. For example: for 4 checkboxes the values are checkbox 1: array index = 0 value = "Y" checkbox 2: array index = 1 value = "Y" checkbox 3: value = "N" : it does not occur in the array checkbox 4: array index = 2 value = "Y" Is there a way to, as it were, complete the array and have all values stored, even the "N" values? So that array index 2 has a value of "N", and array index 3 is "Y". Thxs Sjef