Re: Re: usr VAR value as a VAR Name

From: Date: Thu, 26 Jan 2006 13:09:58 +0000
Subject: Re: Re: usr VAR value as a VAR Name
References: 1 2  Groups: php.general 
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Fisrt thx to all for yours answers, I'm updating the mail because in hte last mail I'didn express my self correctly : EXAMPLE page1.php ======================================= <form action="/page2.php?form=yes" method="post"> $sql_pro ="SELECT Sid FROM table"; $res_pro = @mysql_query( $sql_pro); while ($campo_pro = @mysql_fetch_array($res_pro)) {
     		$sid_pro = $campo_pro["Sid"];  				// $sid_pro = 4
     		$sid_pro = 'p'.$sid_pro;     				// I'm trying to use the value of 		$sid_pro as a VAR name *$sid_pro = p4*			
     		print "<td ><input name='$sid_pro' type= 'radio'  	// Here the Imput Name is a VALUE from Database
value='AAAA'/>* </td>"; // *name = p4 *
      		BLA BLA BLA
} page2.php // I Need to access a value from the form witch it's stored in a VAR called $p4 // The Name of the VAR "$p4" It's stored in my database, so How can I convert a database string to a VAR NAME ======================================= $sqlname = "SELECT Sid FROM Table"; $res = mysql_query ($sqlname) ; while ($campo_pro = mysql_fetch_array($res)) {
      $name1 = $campo_pro["Sid"];  // *$name1 = 4*
      $radio = '$'.'p'.$name1 ; // *$radio = $p4
      ----------------------
      Now the Problem
      **How can I get the Value SOLVE_ME  from the submited form ?*
echo '$radio'; // == $p4 => WRONG i need AAAA // The VALUE of $radio witch is "$p4" is the name of the VAR I need to access, how can I export the VALUE "$p4" AS a VAR Name ? } ================================================================================ James Benson wrote:
if(isset($_POST['NAME_OF_FORM_VALUE'])) { // radio button was selected } Fernando Anchorena wrote:
I'm stuck trying to get work this : This is an example page1.php ======================================= <form action="/page2.php?form=yes" method="post"> $sql_pro ="SELECT Sid FROM table"; $res_pro = @mysql_query( $sql_pro); while ($campo_pro = @mysql_fetch_array($res_pro)) {
     $sid_pro = $campo_pro["Sid"];  //  *sid_pro = 4*
     $sid_pro = 'p'.$sid_pro;     // I'm trying to use de value of $sid_pro as a VAR name *$sid_pro = p4*
     print "<td > *<input name='$sid_pro' type= 'radio'  value='SOLVE_ME'/>* </td>";  // *name=p4 *
      BLA BLA BLA
}
     SUBMIT FORM
======================================= page2.php ======================================= $sqlname = "SELECT Sid FROM Table"; $res = mysql_query ($sqlname) ; while ($campo_pro = mysql_fetch_array($res)) {
      $name1 = $campo_pro["Sid"];  // *$name1 = 4*
      $radio = '$'.'p'.$name1 ; // *$radio = $p4
      ----------------------
      Now the Problem
      **How can I get the Value SOLVE_ME  from the submited form ?*
} ====================================== Thanks in Advance


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