Re: A black thumbnail.

Hi again: I said:

I'm trying to create a thumbnail from a jpeg stored in a long blob in mySQL.

--- -philip said:

imagecreatefromjpeg takes a *filename* not the actual contents of the file itself.

Yes, you are correct that in the statement: $image = imagecreatefromjpeg($fileContent); The variable $fileContent should be a file name -- but it's the contents of the file that the function uses. So, what's the difference between a filename and its contents? Is there a header I should add? Or does the routine require a read operation? I'll look at some other functions. Thanks for your help. tedd -- -------------------------------------------------------------------------------- http://sperling.com/