Re: "!" in front of a variable?

I took me a little while to notice that it wasn't a function declaration :p It's just as Jay said, it's calling "function" with those arguments, where '!$var2' extends to '!(bool)$var2' or "treat/cast this value as/to boolean, and pass it's inverted value" or "NOT $var2". Jay Blanchard wrote:

[snip] I've got some code from someone else I've inherited and need to sort out some problems with. The programmer that wrote it originally was much better than I and programmed a little over my head to say the least. One function that I've come across that has 5 variables as input: function($var1,$var2,!$var2,$var3->cc,$var3->bcc); The question I have is on the 3rd input variable, what does the "!" in front of $var2 do to that variable? [/snip] Hmmm. Looks like a weird mistake, to be sure. If $var2 is boolean it should pass the opposite of its current state. Is $var2 a boolean? It is being passed twice here, once AS and once AS NOT. -- Atentamente, J. Rafael Salazar Magaña Innox - Innovación Inteligente Tel: +52 (33) 3615 5348 ext. 205 / 01 800 2-SOFTWARE rsalazar@innox.com.mx http://www.innox.com.mx