Re: Parse Error

Hi, you need to finish every line with ; $host="localhost" ; $user="ray" ; $password="*****" ; Bye Ray Cantwell wrote:

Hi all, I am a noob and super confused right now. I have some really simple code and i am getting an error that reads: *Parse error*: syntax error, unexpected T_VARIABLE in */var/www/mysql_up.php* on line here is the code: <html> <head><title>Test MySQL</title></head> <body> <!-- mysql_up.php --> <?php $host="localhost" ; $user="ray" ; $password="*****" ; mysql_connect($host,$user,$password) ; $sql="show status"; $result = mysql_query($sql); if ($result == 0) echo "<b>Error " . mysql_errno() . ": "

            . mysql_error() . "</b>";

else { ?> <!-- Table That Displays the results --> <table border="1"> <tr><td><b>Variable_name</b></td><td><b>Value</b>

     </td></tr>

<?php for ($i = 0; $i < mysql_num_rows($result); $i++) {

     echo "<TR>";
     $row_array = mysql_fetch_row($result);
     for ($j = 0; $j < mysql_num_fields(result); $j++)
     {/
       echo "<TD>" . $row_array[$j] . "</td>";
     }
     echo "</tr>";

} ?> </table> <?php } ?> </body></html> I am really confused because i cannot see any obvious errors. any help would be appreciated. Ray.