Re: URL output query

Hi Chris, if the only thing you want is to get the domain (having the whole URL) you have more than one way to solve it. Chris -it's a little akward that Chris answered to Chris- already told you about parse_url(), and since we're talking about strings, I would suggest something like $domain = preg_replace('{^([a-z]+://[^/]+).*$}X', '%1', $uri); Chris wrote:

Greetings PHP folks, Which PHP function do I use if I want to achieve the following : http://www.somesite.com/gallery/pics.php is the url...how do I get it to read only http://www.somesite.com in the browser address bar without the rest of the directory and filename appearing ? -- Atentamente, J. Rafael Salazar Magaña Innox - Innovación Inteligente Tel: +52 (33) 3615 5348 ext. 205 / 01 800 2-SOFTWARE rsalazar@innox.com.mx http://www.innox.com.mx