RE: [PHP] Forms and While Loop

Of course the $CatID variable doesn't show in the action line. According to your code, it is even defined until later in the script. I don't know exactly what you're trying to do but this might work for you: $row = mysql_fetch_row($result); $CatID=$row[1]; echo "<p><form method=\"post\" action=\"$Relative/items.php?CA=$CatID&amp;UID=$UID\"><select name=\"CatList\" size=\"1\">"; do { $Cat=$row[0]; $CatID=$row[1]; echo "<option value=\"$row[0]\"> $row[0] </option>"; } while ($row = mysql_fetch_row($result)) echo "</select><input type=\"submit\" name=\"Submit\" value=\"Go to Category\"></p></form>"; Jason > -----Original Message----- > From: Wayne Michel [mailto:wayne@michel.com.au] > Sent: Wednesday, November 01, 2000 3:37 PM > To: PHP List > Subject: [PHP] Forms and While Loop > > > I am trying to produce a drop-down list. Relevant (I think) code follows: > > echo "<p><form method=\"post\" > action=\"$Relative/items.php?CA=$CatID&amp;UID=$UID\"><select > name=\"CatList\" size=\"1\">"; > while ($row = mysql_fetch_row($result)) > { > $Cat=$row[0]; > $CatID=$row[1]; > echo "<option value=\"$row[0]\"> $row[0] </option>"; > } > echo "</select><input type=\"submit\" name=\"Submit\" > value=\"Go to > Category\"></p></form>"; > > It all works well except the variable $Cat is not showing in the action > line. I have to get it to work with various layouts, but I am at an > impasse. As a new PHP coder, I try to think it through, but this > time I am > stuck. > > Can anyone show me how to get the variable $Cat, inside the loop, > to appear > in the action line. > > Thanks > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net > > _______________________________________________________ Site Design, Hosting, and E-Commerce at www.webpipe.net