Re: mysql_fecth_array() and function call as parameter

Paul Goepfert wrote:

function determineDay () { $return = ""; $query1 = mysql_query("SELECT months FROM Month WHERE m_id = month(curdate())"); $query2 = mysql_query("SELECT dayNum FROM Days WHERE dayNum = day(curdate())"); $query3 = mysql_query("SELECT year FROM Year WHERE year = year(curdate())");

always Always ALWAYS check the error return!!! $query1 = mysql_query("SELECT months FROM Month WHERE m_id = month(curdate())") or die("query1 failed: " . mysql_error()); do this religiously on every single mysql_query. in fact, write a wrapper function to do it for you - that's what i do.

If anyone can find my error please let me know. I have looked at this for about an hour and I can't figure it out.

you probably could have saved an hour by checking the error code. -jsd-