Beginner Help - Array

From: Date: Thu, 13 Apr 2006 20:51:21 +0000
Subject: Beginner Help - Array
Groups: php.general 
Request: Send a blank email to php-general+get-233942@lists.php.net to get a copy of this message
This seems like it should work, but the option statement is just filling in one line of data....hmmmmm... the names have multiple territories (ID's), so I want to have one name associated with one territory ID ( other stuff happens elseware...). //building list of names and their territory matching ID's
                          while($getidsd = mysql_fetch_array($getidsr)){
                          if ($getidsd['employeeid'] != '990'&& $getidsd['employeeid'] != '991') {
	                $salespersonsstor= Array("name"=>$getidsd['fname'].' '.$getidsd['lname'],"idIS"=>$getidsd['employeeid']);
} }
                             asort($salespersonsstor);
                             $salesmanactive='';
                             $salesmann='';
                             $ID1='';
                             foreach ($salespersonsstor as $key => $TheSalesManID) {
                                 switch ($key) {
                                case "name":
                                 $salesmann = $TheSalesManID;
                                break;
                                case "idIS":
                                 $ID1 = $TheSalesManID;
                                          }
                               If (($salesmann != '' && $ID1 != '') && ($salesmanactive != $salesmann)) {
                                 echo '<option value="'.$ID1.'">'.$salesmann.'</option>';
                                 $salesmanactive=$salesmann;
                                 $salesmann='';
                                 $ID1='';
                                 }
                               } 


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