Re: printf and number_format rounding
| From: | Dan Baker | Date: | Wed, 03 May 2006 19:06:29 +0000 |
| Subject: | Re: printf and number_format rounding | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-235399@lists.php.net to get a copy of this message | ||
"Duffy, Scott E" <scott-duffy@uiowa.edu> wrote in message
news:E705A777E3A67646B26D7D4D8F760F6504AE1F7A@medicine-exch3.medicine.uiowa.edu...
Are printf and number_format supposed to round?
echo ($hcount-$lcount)/$hilow." ";
echo number_format(($hcount-$lcount)/$hilow,2,'.','');
0.20833333333333 0.21
0.14583333333333 0.15
0.16666666666667 0.17
0.083333333333333 0.08
Printf ("%.2f",($hcount-$lcount)/$hilow);
Does the same.
It would appear to be. If there is a function to print just to the digit
could you point me in the direction? So I would want 0.20 0.14 0.16
0.08 respectively.
---
You could have the number_format return an extra digit, and then strip that
extra digit off.
$str = number_format(($hcount-$lcount)/$hilow,3,'.','');
$str = substr($str, 0, 4); // (something like this)
DanB