SV: [PHP] One works, but the other doesn't

-----Ursprungligt meddelande----- Från: chris smith [mailto:dmagick@gmail.com] Skickat: den 23 maj 2006 14:13 Till: Jonas Rosling Kopia: PHP List Ämne: Re: [PHP] One works, but the other doesn't On 5/23/06, Jonas Rosling <webmaster@gamearena.se> wrote: > -----Ursprungligt meddelande----- > Från: chris smith [mailto:dmagick@gmail.com] > Skickat: den 23 maj 2006 13:38 > Till: Jonas Rosling > Kopia: PHP List > Ämne: Re: [PHP] One works, but the other doesn't > > > On 5/23/06, Jonas Rosling <webmaster@gamearena.se> wrote: > > I find this problem very strange. I've got two parts of code (allmost the > > same) in different TD's with vars and arrays (with same name) but it's > only > > the top code that gives result. I've allso tryied to rename the vars and > > TD's in the bottom without any luck. The only vars/arrays that I haven't > > mind changing name on yet are some dynamic, like: > > > > ${$row[0]} = array(); > > > > ${$row[0]}[$row[1]] = $row[2]; > > > > But I think this could be the main cause, but I'm not really sure. If I > > delete the top code the bottom works. Any idéas any one? > > Without seeing the whole code involved, my guess is you're resetting > the array with every loop. > > Guesses don't help but that's all we can do without seeing any actual code. > > Okej, all the code follows bellow. Remember that part 1 allways works. And > they work all seperatly. Man you do things the hard way. Why use all those variable variables? $my_data = array(); // Loppar igenom raderna while($row=mysql_fetch_assoc($result)) { $code = $row['salesperson_code']; if (!isset($my_data[$code])) { $my_data[$code] = array( 'description' => $row['description'], 'total' => $row['totalt'], 'antal' => $row['antal'] ); } else { $my_data[$code]['description'] = $row['description']; } } ------------------------- Well, I'm kind of a newbie at this. So you think this will solve my problem? // Jonas -- Postgresql & php tutorials http://www.designmagick.com/