RE: [PHP] Why does this preg_replace function not work?

[snip] "[" . $tags . "]" [/snip] This in the regex would need to be "\[" . $tags . "\]" as the square brackets ([]) represent a character class in regular expressions, so must be escaped to be matched literally Also /'s should be escaped (\/) There may be more mistakes but I thought I'd point this one out :) HTH Dan -- Dan Parry Senior Developer Virtua Webtech Ltd http://www.virtuawebtech.co.uk -----Original Message----- From: Dave M G [mailto:martin@autotelic.com] Sent: 26 May 2006 10:26 To: php-general@lists.php.net Subject: [PHP] Why does this preg_replace function not work? PHP List, In the code below, I want to take the text within $content, and change every instance of [h3] into <h3>, and every instance of [/h3] into </h3>. And then do the same for [em], [/em], [strong], and so on. However, this code does absolutely nothing to the text stored in content: $tags = array ("h3", "em", "strong", "hr"); $content = preg_replace("[" . $tags . "]", "<" . $tags . ">", $content); $content = preg_replace("[/" . $tags . "]", "</" . $tags . ">", $content); Clearly I've either misunderstood the use of preg_replace(), or regular expressions, or arrays, despite having looked them up in the PHP online manual. I also tried str_replace(), but predictably that did not help. As far as I understand it, it does not accept arrays. What am I doing wrong in the above code? And can the two preg_replace() commands be achieved in one line? Thank you for any advice. -- Dave M G -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- No virus found in this incoming message. Checked by AVG Free Edition. Version: 7.1.392 / Virus Database: 268.7.0/346 - Release Date: 23/05/2006 -- No virus found in this outgoing message. Checked by AVG Free Edition. Version: 7.1.392 / Virus Database: 268.7.0/346 - Release Date: 23/05/2006