Re: Re: Retrieving Content

On 6/3/06, Adam Zey <azey@nit.ca> wrote:

Rodrigo de Oliveira Costa wrote: I just discovered the problem I have to retrieve the output of the site and not the url since its dynamic. Ca I do it like retrieve the output of this url: www.tryout.com/1/2/ And of course store it on a variable? How to do it? I founr the func below but couldnt understand how to make it work with a url. Thanks guys, Rodrigo ob_start(); include('file.php'); // Could be a site here? What should I do to retrieve it from an url? $output = ob_get_contents(); ob_end_clean(); Umm..... As I said, just use file_get_contents(): $file = file_get_contents("http://www.tryout.com/1/2/");

Assuming allow_url_fopen is on. If not, you could try using curl - see http://www.php.net/curl -- Postgresql & php tutorials http://www.designmagick.com/