Re: Re: [PHP] transform RDF to HTML via XSL and PHP
| From: | Mario Pavlov | Date: | Mon, 12 Jun 2006 20:58:31 +0000 |
| Subject: | Re: Re: [PHP] transform RDF to HTML via XSL and PHP | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-237845@lists.php.net to get a copy of this message | ||
>Mario Pavlov wrote:
>
>> nope
>> it doesn't work like this
>> still the same result
>> I think the problem is in the way that I'm accessing the elements
>> how exactly this should be done ?...
>
>Its due to default namespaces in the feed. The item elements and its
>child elements are in the default namespace:
>http://my.netscape.com/rdf/simple/0.9/
>
>You need to declare this namespace with a prefix in order to access the
>elements within the stylesheet (same as using XPath).
>
>i.e. the following stylesheet uses the prefix rdf9 for that namespace.
>
><?xml version="1.0" encoding="ISO-8859-1"?>
><xsl:stylesheet version="1.0"
>xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
>xmlns:rdf9="http://my.netscape.com/rdf/simple/0.9/">
><xsl:output method='html' version='1.0' encoding='UTF-8'
>indent='yes'/>
>
><xsl:template match="/">
> <html>
> <body>
> <table border="1">
> <xsl:for-each select="//rdf:RDF/rdf9:item">
> <tr>
> <td><xsl:value-of select="rdf9:title"/></td>
> <td><xsl:value-of select="rdf9:link"/></td>
> </tr>
> </xsl:for-each>
> </table>
> </body>
> </html>
></xsl:template>
></xsl:stylesheet>
>
>Rob
>
>--
>rrichards@ctindustries.net
>author of Pro PHP XML and Web Services from Apress
>
thank you man!! :)
I can't believe it, it just WORKS :)
thank you very much!
it took me about a week ...
thank you again! :)
god bless you :)
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