Re: Ok next php problem

At 7:21 PM -0500 6/18/06, Rob W. wrote: >I got the previous question answered, Now here's my next problem. > >With the numbers displaying correctly again I got: > >1 >2 >3 >4 >5 >6 >7 >10 >11 >12 >13 >14 >15 >16 >17 >18 >19 >20 >21 >22 >25 > >listed in that order in the database > >Now i'm trying to figure out how to write a syntax saying that if like number 8 isnt >listed, display it. > >I've tried doing a > >if ($count != $data) { > echo "$data"; >} >$count++; > >But when I get to like id number 9 it dont work right because the next entrie is displayed as 10 >in the db. So that's my problem is to try and display only them numbers that are not in there. >I have also tried putting the numbers in to an array and matching from there but it still >come's up as the same as above. > >- Rob Rob: Why? If you want to show the number of records in your dB, then just show them. If you want a counter, then add a counter but don't list the id number. Besides, why would you want to anyway? tedd -- ------------------------------------------------------------------------------------ http://sperling.com http://ancientstones.com http://earthstones.com