RE: [PHP] <input type = image ... >

You should be able to do something like this: In your INPUT tag: <INPUT TYPE="image" ... ... ... ... NAME="myimage1"> (do not include the VALUE attribute) then in the page that your form submits to: if (isset($myimage1_x)) { do something useful or possibly not quite so useful; } Since your input type is an image, the _x addition to what you named your input image is implied. From what I understand the $myimage1_x variable will be set to the x coordinate where the user clicked on the image. Someone can chime in and correct me if that is wrong though....in either case, you merely need to check if that variable is set....you shouldn't need its value. HTH Sam Masiello System Analyst Chek.Com (716) 853-1362 x289 smasiello@chekinc.com -----Original Message----- From: Russ Abbott [mailto:RAbbott@CalStateLA.edu] Sent: Monday, November 06, 2000 10:30 AM To: php-general@lists.php.net Subject: [PHP] <input type = image ... > I'd like to use a tag such as <input type=image name=n value=v> to pass v as a value of $n, but it doesn't seem to work. I have this tag inside a form, and clicking on the image does trigger the program pointed to by the form, but $n is not bound to anything. (Other <input ... > tags have their values posted properly.) If I change type=image to type=submit, a button is generated and $n is bound to v as expected. Is there some way to substitute an image for a button and associate data with the image? I want to have a group of images, each with a different data value, and then have the program be told which image was clicked. Thanks. -- Russ Abbott