Re: Please help me with in_array
| From: | Jochem Maas | Date: | Fri, 04 Aug 2006 22:29:05 +0000 |
| Subject: | Re: Please help me with in_array | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-240172@lists.php.net to get a copy of this message | ||
Chris G wrote:
> I have already tried using
>
> foreach($_GET['question'] as $key => $value)
>
> the in_array function does not work with it for some reason.
'does not work with it' ??
use var_dump(); to see what's actually in your variables.
>
>
> On 8/5/06, *Jochem Maas* <jochem@iamjochem.com
> <mailto:jochem@iamjochem.com>> wrote:
>
> foreach($_GET['question'] as $key => $value) {
>
var_dump($key, $value);
> > if(!in_array($key, $_SESSION['question'])) {
> > print "not matched lets update<br>".
> > "$_GET[question][$key]"; // HERE I WANT IT TO
> SHOW $key
> > is 10 and its value should be 1 (as printed in the Array above)
> > }
> > else {
> > print "matched";
> > }
> > }
> >
> >
> >
> > Where it gets to the section "not matched" I need to print out
> from the
> > question array question[$key][$value] (question '10' => '1' as
> > above)
> >
> >
> >
> > I am not sure if I am even making sense here anymore...
> >
> > Thanks in advance
> >
> >
> > Chris
> >
>
>