Re: How to get rid off empty elements of an array?
| From: | John Wells | Date: | Mon, 07 Aug 2006 15:38:03 +0000 |
| Subject: | Re: How to get rid off empty elements of an array? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-240265@lists.php.net to get a copy of this message | ||
Check the 5th and 6th fields. Something is in one of them. Because
based on your checks, it will work:
[php]
$first_array = array(
'first',
'second',
'third',
'',
'',
'');
foreach ($first_array as $value)
{
if (!empty($value)) $second_array[] = $value;} var_dump($second_array); foreach ($first_array as $value) {
if ($value != '') $third_array[] = $value;} var_dump($third_array); [/php] HTH, John W On 8/7/06, afan@afan.net <afan@afan.net> wrote:
Hi to all! I have a form with 6 text fields where visitor has to enter product serial number (same type data). he has to enter AT LEAST ONE. for ($i=0; $i<6; $i++) {echo '<input type="text" name="PSN['.$i.']" value="'.$PSN[$i].'"size="25">'; } After the form is submitted I'm getting an array Array ([0] => abc123 [1] => ddd111 [2] => poi987 [3] => [4] => [5] =>) Now, I need to get rid off empty elements of the array, to get this: Array ([0] => abc123 [1] => ddd111 [2] => poi987) To do that I tried: foreach ($PSN as $value) {if (!empty($value)) $PSN_New[] = $value;} but every time I'm getting one additional element of the array: I tried foreach ($PSN as $value) {if ($value != '') $PSN_New[] = $value;} too - same result. Array ([0] => abc123 [1] => ddd111 [2] => poi987 [3] =>) No space or anything else is "entered" in 4th field. What I'm doing wrong? Thanks for any help. -afan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php