Re: Include and require

Dave Goodchild wrote:

I use a config file too. That was a sanity check. The file extract looked like this: $months = array(1 => 'January', 2 => 'February', 3 => 'March', 4 => 'April', 5 => 'May', 6=> 'June',

                7 => 'July', 8 => 'August', 9 => 'September', 10 => 'October', 11 => 'November', 12 => 'December');

which was called in with require_once. The reference to $months in the calling page, checked with var_dump, was NULL. When I wrapped it like this: function getmonths() {

    $months = array(1 => 'January', 2 => 'February', 3 => 'March', 4 => 'April', 5 => 'May', 6=> 'June',
                7 => 'July', 8 => 'August', 9 => 'September', 10 => 'October', 11 => 'November', 12 => 'December');
    return $months;

} it worked. Not sure why the simple variable didn't work. On 14/08/06, *Adam Zey* <azey@nit.ca <mailto:azey@nit.ca>> wrote:

    Dave Goodchild wrote:

Hi all - I have several require_once statements in my web app to

    load in

small function libraries. A common one bundles a variety of

    functions to

handle date math and map month numbers to month names. I

    originally defined

an array in that file plus a bunch of functions but when I

    loaded the page,

the array variable, referenced further down the page, was NULL.

    I wrapped a

function def around the array and returned it and all was fine. I may be suffering from mild hallucinations, but can you not define variables in a required file? It is not a scope issue as the

    array variable

is referenced in the web page, not in any function.

    I know for a fact that you can define variables in PHP 4 and 5.
    The idea
    behind include and require is little more complex than copying and
    pasting the code. Many of my scripts include a config.php which has
    various variables created with setting information.

    Regards, Adam Zey.

-- http://www.web-buddha.co.uk http://www.projectkarma.co.uk Was the $months variable created inside an if statement or something else? PHP's rules of scope say that variables created inside a code block (like an if, a for, a while, a foreach), they stop existing the moment you exit that code block. So this:

$foo = "bar"; if ( $foo == "bar" ) { $baz = "narf"; } echo $baz; That code will output nothing, because $baz is empty by the time I try to output it. The solution that I use is this: $foo = "bar"; $baz = ""; if ( $foo == "bar" ) { $baz = "narf"; } echo $baz; In which case the output would be "narf", because the variable existed before I changed it in the if. This sounds like it might be your problem, though I can't know without seeing the code. Regards, Adam Zey.