Re: Capturing System output
| From: | Ray Hauge | Date: | Tue, 15 Aug 2006 14:32:45 +0000 |
| Subject: | Re: Capturing System output | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-240706@lists.php.net to get a copy of this message | ||
On Tuesday 15 August 2006 09:19, Brad Bonkoski wrote:
> Hello All..
>
> Had this problem in the past, and always programmed around it, but
> wondering if there is an easier way.
>
> Good Example:
> Creating a setup for connecting to a mysql database. Want to do
> something simple to make sure they have entered a valid
> username/password for the database.
> So, the idea is something like:
> $rc = exec("mysql -u $user -p{$pass}", $output);
> The problem is one error, the stderr does not go to the output array,
> but rather to the screen.
>
> Previously I would redirect the stderr to a file, and then evaluate the
> contents of the file, but is there an easier way to get this into the
> PHP variable with no risk of having the output make it through to the
> screen?
>
> Thanks
> -Brad
I'd take a look at shell_exec. There'sa comment about capturing stderr. I'm
not sure if shell_exec captures stderr, but it should at least point you in
the right direction. Just do a search for stderr and you should find some
good info.
--
Ray Hauge
Programmer/Systems Administrator
American Student Loan Services
www.americanstudentloan.com
1.800.575.1099